Chemistry_Class-12_Ch-1_Solution_Topic-4_Ideal And Non-Ideal Solution 1 / 20 1)A solution with negative deviation among the following is A) Ethanol - Acetone B) Chlorobenzene - Bromobenzene C) Chloroform - Acetone D) Benzene -Toluene 2 / 20 2. A solution of acetone in ethanol A) Behaves like a near ideal solution B) Obeys Raoult's law C) Shows a negative deviation from Raoult's law D) Shows a positive deviation from Raoult's law 3 / 20 3) A binary liquid solution is prepared by mixingn n -heptane and ethanol. Which one of the following statements is correct regarding the behaviour of the solution A) The solution formed is an ideal solution B) The solution is non-ideal, showing +ve deviation from Raoult's Law C) The solution is non-ideal, showing -ve deviation from Raoult's Law D) n-heptane shows +ve deviation while ethanol shows- ve deviation from Raoult's Law 4 / 20 4) One component of a solution follows Raoult's law over the entire range 0≤ x1 ≤ 1. The second component must follow Raoult's law in the range when x₂ is A) Close to zero B) Close to 1 C) 0 ≤ x2 ≤ 0.5 D) 0 ≤ x 2 ≤ 1 5 / 20 5) Considering the formation, breaking and strength of hydrogen bond, predict which of the following mixtures will show a positive deviation from Raoult's law A) Methanol and acetone B) Chloroform and acetone C) Nitric acid and water D) Phenol and aniline 6 / 20 6. On the basis of information given below mark the correct option Information: (i) In bromoethane and chloroethane mixture intermolecular interactions of A-A and B-B type are nearly same as A-B type interactions (ii) In ethanol and acetone mixture A-A or B-B type intermolecular interactions are stronger than A-B type interactions (iii) In chloroform and acetone mixture A-A or B-B type intermolecular interactions are weaker than A-B type interactions A) Solution (ii) and (iii) will follow Raoult's law B) Solution (i) will follow Raoult's law C) Solution (ii) will show negative deviation from Raoult's law D) Solution (iii) will show positive deviation from Raoult's law 7 / 20 7. Which of the following liquid pairs shows a positive deviation from Raoult's law A) Water-nitric acid B) Benzene-methanol C) Water-hydrochloric acid D) Acetone-chloroform 8 / 20 8. Identify the mixture that shows positive deviation from Raoult's law A) CHCl₃ + (CH₃)₂CO B) (CH₃)₂CO + C₆H₅NH₂ C) CHCl₃ + C₆H₆ D) (CH₃)₂CO + CS₂ 9 / 20 9. Which of the following does not show positive deviation from Raoult's law A) Benzene-Chloroform B) Benzene-Acetone C) ) Benzene-Ethanol D) Benzene-Carbon tetrachloride 10 / 20 10. Which of the following does not show negative deviation from Raoult's law A) Acetone-Chloroform B) Acetone-Benzene C) Chloroform-Ether D) Chloroform-Benzene 11 / 20 11. All form ideal solutions except A) C₂H₅Br and C₂H₅I B) C₆H₅Cl and C₆H₅Br C) C₆H₆ and C₆H₅CH₃ D) C₂H₅I and C₂H₅OH 12 / 20 12. Which property is shown by an ideal solution A) It follows Raoult's law B) ∆H mix = 0 C) ∆Vmix=0 D) All of these 13 / 20 13. Which of the following is not correct for ideal solution A) ∆S mix = 0 B) ∆H mix =0 C) It obeys Raoult's law D) ∆V mix =0 14 / 20 14. Which one of the following is incorrect for ideal solution A) ) ∆G mix = 0 B) ∆ H mix = 0 C) ∆ U mix = 0 D) ∆ P = P obs- P calculated by Raoult's law = 0 15 / 20 15) Formation of a solution from two components can be considered as (i) Pure solvent → separated solvent molecules, ∆H1 (ii) Pure solute → separated solute molecules , ∆ H₂ (iii) Separated solvent and solute molecules → solution, ∆H3 Solution so formed will be ideal if…. A) ∆ H soln = ∆H3 – ΔΗ1 – ΔΗ2 B) ∆ H soln = ∆ Η1 + ΔΗ2 + ΔΗ3 C) ∆ Hsoln = ∆ Η1 +∆ Η2- ΔΗ3 D) ∆ Hsoln = ΔΗ1- ΔΗ2 - ΔΗ3 16 / 20 16) A non ideal solution was prepared by mixing 30 mL chloroform and 50 mL acetone. The volume of mixture will be A) > 80 mL B) < 80 mL C) 80 mL D) ) ≥ 80 mL 17 / 20 17) When two liquid A and B are mixed then their boiling points becomes greater than both of them. What is the nature of this solution A) Ideal solution B) Positive deviation with non ideal solution C) Negative deviation with non ideal solution. D) Normal solution 18 / 20 18) Liquids A and B form an ideal solution in the entire composition range. At 350K, the vapour pressures of pure A and pure B are 7x103 Pa and 12x103 Pa. respectively. The composition of the vapour in equilibrium with a solution containing 40 mole percent of A at this temperature is: A) XA =0.28; XB = 0.72 B) XA =0.76; XB = 0.24 C) XA =0.37; XB = 0.63 D) XA = 0.4 ; XB = 0.6 19 / 20 19). For an ideal solution, the correct option is A) ∆mixG = 0 at consiant T and P B) ∆mixS = 0 at constant T and P C) ∆mixV ≠0 at constant T and P D) ∆mix H =0 at constant T and P 20 / 20 20. What does point S indicate in the given figure ? A) Both liquid have same partial pressure and mole fraction B) Both liquid have same mole fraction but different partial C) Both liquid have different partial pressure and mole fraction D) Both liquid have different mole fractions. But same partial Your score isThe average score is 0% 0% Exit
