Chemistry_Class-11_Chapter-3_Topic-5_ELECTRONEGATIVITY 1 / 23 1. Between HF, HCl , HBr and HI, HF has the highest ionic character because (a) F has the highest electron affinity (b) In HF, electronegativity difference is highest (c) F- ion has the highest value of ionic radius (d) Atomic orbitals of H and F have almost similar energy 2 / 23 2. On Puling scale which of the following does not have electronegativity ≥ 3.0 (a) Oxygen (b) Nitrogen (c) Chlorine (d) Bromine 3 / 23 3. An atom with high electronegativity has (a) Large size (b) High ionization potential (c) Low electron affinity (d) Low ionization potential 4 / 23 4. The outmost electronic configuration of the most electronegative elements is (a) ns2 np3 (b) ns2 np4 (c) ns2 np5 (d) ns2 np6 5 / 23 5. Which of the following is second most electronegative element (a) Chlorine (b) Oxygen (c) Sulphur (d) Fluorine 6 / 23 6. Which of the following is the most electropositive elements (a) Aluminium (b) Magnesium (c) Phosphorus (d) sulphur 7 / 23 7. Most electronegative element is (a) Al (b) C (c) Si (d) Be 8 / 23 8. The electronegativity of the following elements increases in the order (a) C , N , Si , P (b) N , Si ,C , P (c) Si , P , C , N (d) P, Si , N , C 9 / 23 9. Which one of the following has the highest electronegativity (a) Br (b) Cl (c) P (d) Si 10 / 23 10. Arrange F, Cl, O, N in the decreasing order of electronegativity (a) O > F > N > Cl (b) F > N > Cl > O (c) Cl > F > N > O (d) F > O > N > Cl 11 / 23 11. Which one of the following represents the electronic configuration of the most electropositive element (a) [He] 2s1 (b) [Xe] 6s1 (c) [He] 2s2 (d) [Xe] 6s2 12 / 23 12. The chemical elements are arranged in the order of increasing electronegativities in the sequence (a) P, Si, Se, Br, N (b) Si, Se, P, Br, N (c) Si, P, Se, Br, N (d) Se, P, Si, Br, N 13 / 23 13. Which of the following is the most electronegative (a) F (b) He (c) Ne (d) Na 14 / 23 14. Pauling’s equation for determining the electronegativity of an element’s (a) XA – XB = 0.208√∆ (b) XA + XB = 0.208 √∆ (c) XA – XB = 0.208 ∆2 (d) XA – XB = √∆ 15 / 23 15. The property of attracting electrons by the halogen atom in a molecular is called (a) Ionization potential (b) Electron affinity (c) Electronegativity (d) Electronic attraction 16 / 23 16. The most polar bond is (a) O – F (b) N – Cl (c) N – F (d) N – N 17 / 23 17. Which is the correct order of electronegativities (a) F > N C (b) F > N > O > C (c) F < N < O < C (d) F > N > O < C 18 / 23 18. In the following, the element with the highest electro positivity is (a) Copper (b) Cesium (c) Barium (d) Chromium 19 / 23 19. Which of these have no unit (a) Electronegativity (b) Electron affinity (c) Ionization energy (d) Excitation potential 20 / 23 20. The correct order of decreasing electronegativity values among the elements I- beryllium, II-oxygen, III-nitrogen and IV-magnesium is (a) (II) > (III) > (I) > (IV) (b) (III) > (IV) > (II) > (I) (c) (I) > (II) > (III) > (IV) (d) (I) > (II) > (IV) > (III) (e) (II) > (III) > (IV) > (I) 21 / 23 21. Increasing order of electronegativity is (a) Bi < P < S < Cl (b) P < Bi < S < Cl (c) S < Bi < P < Cl (d) Cl < S < Bi < P 22 / 23 22. In general, the properties that decrease and increase down a group in the periodic table, respectively, are: (a) Atomic radius and electronegativity (b) Electronegativity and atomic radius (c) Electron gain enthalpy and electronegativity (d) Electronegativity and electron gain enthalpy 23 / 23 23. The correct option with respect to the Pauling electronegativity values of the elements is :- (a) Te > Se (b) Ga < Ge (c) Si < Al (d) P > S Your score isThe average score is 0% 0% Exit